What is 4a^{-3}b^{-2} ?

The solution to 4a^{-3}b^{-2} is 4/(a^3b^2)

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simplify 4a^{-3}b^{-2}

simplify

4 a^{- 3} b^{- 2}

\frac{4}{a ^{3} b ^{2}}

Solution steps

4 a^{- 3} b^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

a^{- 3} = \frac{1}{a ^{3}}

= 4 \cdot \frac{1}{a ^{3}} b^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

b^{- 2} = \frac{1}{b ^{2}}

= 4 \cdot \frac{1}{a ^{3}} \cdot \frac{1}{b ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{4 \cdot 1 \cdot 1}{a ^{3} b ^{2}}

Multiply the numbers:

4 \cdot 1 \cdot 1 = 4

= \frac{4}{a ^{3} b ^{2}}

\frac{x ^{2}}{x ^{2}}

x^{2} - x - 14 = 0

λ^{2} - 4 λ + 5 = 0

3 x^{2} = 2 x + 3

4 x + 34 = 106