What are the solutions to the equation -5x^2+7x=-9 ?

The solutions to the equation -5x^2+7x=-9 are x=-(-7+sqrt(229))/(10),x=(7+sqrt(229))/(10)

Find the zeros of -5x^2+7x=-9

The zeros of -5x^2+7x=-9 are x=-(-7+sqrt(229))/(10),x=(7+sqrt(229))/(10)

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- 5 x^{2} + 7 x = - 9

x = - \frac{- 7 + 229}{10}, x = \frac{7 + 229}{10}

Solution steps

- 5 x^{2} + 7 x = - 9

Move

9

to the left side

- 5 x^{2} + 7 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 5 ) \cdot 9}{2 ( - 5 )}

7^{2} - 4 (- 5) \cdot 9 = 229

x_{1, 2} = \frac{- 7 \pm 229}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 7 + 229}{2 ( - 5 )}, x_{2} = \frac{- 7 - 229}{2 ( - 5 )}

x = \frac{- 7 + 229}{2 ( - 5 )} : - \frac{- 7 + 229}{10}

x = \frac{- 7 - 229}{2 ( - 5 )} : \frac{7 + 229}{10}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 229}{10}, x = \frac{7 + 229}{10}

x^{2} = 80

\frac{4}{9 + i}

4 x^{2} = - 12 x - 9

- 6 \cdot \frac{5}{3}

What are the solutions to the equation -5x^2+7x=-9 ?
The solutions to the equation -5x^2+7x=-9 are x=-(-7+sqrt(229))/(10),x=(7+sqrt(229))/(10)
Find the zeros of -5x^2+7x=-9
The zeros of -5x^2+7x=-9 are x=-(-7+sqrt(229))/(10),x=(7+sqrt(229))/(10)