What are the solutions to the equation 3(x-2)^2=40 ?

The solutions to the equation 3(x-2)^2=40 are x=(2sqrt(10))/(sqrt(3))+2,x=-(2sqrt(10))/(sqrt(3))+2

Find the zeros of 3(x-2)^2=40

The zeros of 3(x-2)^2=40 are x=(2sqrt(10))/(sqrt(3))+2,x=-(2sqrt(10))/(sqrt(3))+2

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3 (x - 2)^{2} = 40

x = \frac{2 10}{3} + 2, x = - \frac{2 10}{3} + 2

Solution steps

3 (x - 2)^{2} = 40

Divide both sides by

3

(x - 2)^{2} = \frac{40}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = \frac{40}{3} : x = \frac{2 10}{3} + 2

Solve

x - 2 = - \frac{40}{3} : x = - \frac{2 10}{3} + 2

The solutions to the quadratic equation are:

x = \frac{2 10}{3} + 2, x = - \frac{2 10}{3} + 2

3 x - 15 + 5 x - 23 = 90

\frac{84}{28} \cdot \frac{2}{3} \cdot 65

∣ 3 x - 1 ∣ + 4 = 0

\frac{2}{2} + 1.75 - \frac{44}{25}

2 x - 3 = 1 + 3 x

What are the solutions to the equation 3(x-2)^2=40 ?
The solutions to the equation 3(x-2)^2=40 are x=(2sqrt(10))/(sqrt(3))+2,x=-(2sqrt(10))/(sqrt(3))+2
Find the zeros of 3(x-2)^2=40
The zeros of 3(x-2)^2=40 are x=(2sqrt(10))/(sqrt(3))+2,x=-(2sqrt(10))/(sqrt(3))+2