What are the solutions to the equation t^2=t ?

The solutions to the equation t^2=t are t=1,t=0

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t^2=t

t^{2} = t

t = 1, t = 0

Solution steps

t^{2} = t

Move

t

to the left side

t^{2} - t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

t_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, t_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

t = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

t = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 1, t = 0

- 7 + m = 8

7 \cdot 3

- 7 = 6 + y

n^{2} - 9

4 (x - 1) (x - 5) \geq 0

What are the solutions to the equation t^2=t ?
The solutions to the equation t^2=t are t=1,t=0
Find the zeros of t^2=t
The zeros of t^2=t are t=1,t=0