What are the solutions to the equation -2x^2+6x+8=0 ?

The solutions to the equation -2x^2+6x+8=0 are x=-1,x=4

Find the zeros of -2x^2+6x+8=0

The zeros of -2x^2+6x+8=0 are x=-1,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + 6 x + 8 = 0

x = - 1, x = 4

Solution steps

- 2 x^{2} + 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 2 ) \cdot 8}{2 ( - 2 )}

6^{2} - 4 (- 2) \cdot 8 = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 ( - 2 )}, x_{2} = \frac{- 6 - 10}{2 ( - 2 )}

x = \frac{- 6 + 10}{2 ( - 2 )} : - 1

x = \frac{- 6 - 10}{2 ( - 2 )} : 4

The solutions to the quadratic equation are:

x = - 1, x = 4

(- 324) (520)

w + 9 < 23

4 x^{- \frac{9}{2}} + 4 x^{- \frac{7}{2}} + x^{- \frac{5}{2}}

- 3 (2)^{2}

(\frac{3}{5})^{- 3}

What are the solutions to the equation -2x^2+6x+8=0 ?
The solutions to the equation -2x^2+6x+8=0 are x=-1,x=4
Find the zeros of -2x^2+6x+8=0
The zeros of -2x^2+6x+8=0 are x=-1,x=4