What are the solutions to the equation y^2+7=6y ?

The solutions to the equation y^2+7=6y are y=3+sqrt(2),y=3-sqrt(2)

Find the zeros of y^2+7=6y

The zeros of y^2+7=6y are y=3+sqrt(2),y=3-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} + 7 = 6 y

y = 3 + 2, y = 3 - 2

Solution steps

y^{2} + 7 = 6 y

Move

6 y

to the left side

y^{2} + 7 - 6 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 6 y + 7 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 7 = 22

y_{1, 2} = \frac{- ( - 6 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 2}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 2 2}{2 \cdot 1}

y = \frac{- ( - 6 ) + 2 2}{2 \cdot 1} : 3 + 2

y = \frac{- ( - 6 ) - 2 2}{2 \cdot 1} : 3 - 2

The solutions to the quadratic equation are:

y = 3 + 2, y = 3 - 2

36 w^{2} - 49

0 = 2 + 24.5 t - 4.9 t^{2}

x^{2} + 8 x = 65

5 x^{2} - 18 x + 9 \leq 0

p^{2} + 3 p - 54

What are the solutions to the equation y^2+7=6y ?
The solutions to the equation y^2+7=6y are y=3+sqrt(2),y=3-sqrt(2)
Find the zeros of y^2+7=6y
The zeros of y^2+7=6y are y=3+sqrt(2),y=3-sqrt(2)