What are the solutions to the equation 4^2+2^2=c^2 ?

The solutions to the equation 4^2+2^2=c^2 are c=2sqrt(5),c=-2sqrt(5)

Find the zeros of 4^2+2^2=c^2

The zeros of 4^2+2^2=c^2 are c=2sqrt(5),c=-2sqrt(5)

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4^{2} + 2^{2} = c^{2}

c = 25, c = - 25

Decimal Notation

c = 4.47213 \dots, c = - 4.47213 \dots

Solution steps

4^{2} + 2^{2} = c^{2}

Switch sides

c^{2} = 4^{2} + 2^{2}

Simplify

4^{2} + 2^{2} : 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 20, c = - 20

20 = 25

- 20 = - 25

c = 25, c = - 25

30 x - 18 > 252

\frac{2}{5} + \frac{5}{20}

- 4.3 x - 1.8 = 7.5 x - 6.3

lo g_{3} (\frac{1}{4})

x^{2} + 2 x + 1 = 2 x + 5

What are the solutions to the equation 4^2+2^2=c^2 ?
The solutions to the equation 4^2+2^2=c^2 are c=2sqrt(5),c=-2sqrt(5)
Find the zeros of 4^2+2^2=c^2
The zeros of 4^2+2^2=c^2 are c=2sqrt(5),c=-2sqrt(5)