What is factor 4x^3(4x-8)^2+x^4(2)(4x-8)(8) ?

The solution to factor 4x^3(4x-8)^2+x^4(2)(4x-8)(8) is 128x^3(x-2)(x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 4x^3(4x-8)^2+x^4(2)(4x-8)(8)

factor

4 x^{3} (4 x - 8)^{2} + x^{4} (2) (4 x - 8) (8)

128 x^{3} (x - 2) (x - 1)

Solution steps

4 x^{3} (4 x - 8)^{2} + x^{4} (2) (4 x - 8) (8)

Factor out common term

x^{3} (4 x - 8) : x^{3} (4 x - 8) (4 (4 x - 8) + x \cdot 2 \cdot 8)

= x^{3} (4 x - 8) (4 (4 x - 8) + x \cdot 2 \cdot 8)

Factor

4 x - 8 : 4 (x - 2)

Factor

4 (4 x - 8) + x \cdot 2 \cdot 8 : 32 (x - 1)

= x^{3} \cdot 4 (x - 2) \cdot 32 (x - 1)

Multiply the numbers:

4 \cdot 32 = 128

= x^{3} \cdot 128 (x - 2) (x - 1)

= 128 x^{3} (x - 2) (x - 1)

5 x^{3} + 25 x^{2} + 30 x

a^{2} + 6 a + 9 - b^{2}

2 x^{2} + 4 x - 9 = 0

5 x - 1 (8 - x) = 10

∣ 5 x - 4 ∣ \geq 6

What is factor 4x^3(4x-8)^2+x^4(2)(4x-8)(8) ?
The solution to factor 4x^3(4x-8)^2+x^4(2)(4x-8)(8) is 128x^3(x-2)(x-1)