What are the solutions to the equation 4x^2+5x-6=0 ?

The solutions to the equation 4x^2+5x-6=0 are x= 3/4 ,x=-2

Find the zeros of 4x^2+5x-6=0

The zeros of 4x^2+5x-6=0 are x= 3/4 ,x=-2

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4 x^{2} + 5 x - 6 = 0

x = \frac{3}{4}, x = - 2

Solution steps

4 x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 6) = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 \cdot 4}, x_{2} = \frac{- 5 - 11}{2 \cdot 4}

x = \frac{- 5 + 11}{2 \cdot 4} : \frac{3}{4}

x = \frac{- 5 - 11}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - 2

(- 25)^{2}

n (1 - \frac{t}{1 - x})^{n - 1} \cdot \frac{1}{1 - x}

2 x^{2} + 6 x + 8 = 0

(1 + 2) (1 - 2)

x^{2} + 10 x + 25 < 0

What are the solutions to the equation 4x^2+5x-6=0 ?
The solutions to the equation 4x^2+5x-6=0 are x= 3/4 ,x=-2
Find the zeros of 4x^2+5x-6=0
The zeros of 4x^2+5x-6=0 are x= 3/4 ,x=-2