What are the solutions to the equation (4x+1)^2=12 ?

The solutions to the equation (4x+1)^2=12 are x=(2sqrt(3)-1)/4 ,x=(-2sqrt(3)-1)/4

Find the zeros of (4x+1)^2=12

The zeros of (4x+1)^2=12 are x=(2sqrt(3)-1)/4 ,x=(-2sqrt(3)-1)/4

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(4 x + 1)^{2} = 12

x = \frac{2 3 - 1}{4}, x = \frac{- 2 3 - 1}{4}

Solution steps

(4 x + 1)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 1 = 12 : x = \frac{2 3 - 1}{4}

Solve

4 x + 1 = - 12 : x = \frac{- 2 3 - 1}{4}

The solutions to the quadratic equation are:

x = \frac{2 3 - 1}{4}, x = \frac{- 2 3 - 1}{4}

27 + 53

\frac{\frac{2}{( x + h ) ^{2}} - \frac{2}{x ^{2}}}{h}

\frac{4 i}{- 8 - 7 i}

\frac{1}{3} + \frac{5}{8}

∣ x + 4 ∣ = ∣ x - 7 ∣

What are the solutions to the equation (4x+1)^2=12 ?
The solutions to the equation (4x+1)^2=12 are x=(2sqrt(3)-1)/4 ,x=(-2sqrt(3)-1)/4
Find the zeros of (4x+1)^2=12
The zeros of (4x+1)^2=12 are x=(2sqrt(3)-1)/4 ,x=(-2sqrt(3)-1)/4