What are the solutions to the equation 2x^2+8x+14=0 ?

The solutions to the equation 2x^2+8x+14=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

Find the zeros of 2x^2+8x+14=0

The zeros of 2x^2+8x+14=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

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2 x^{2} + 8 x + 14 = 0

x = - 2 + 3 i, x = - 2 - 3 i

Solution steps

2 x^{2} + 8 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

Simplify

8^{2} - 4 \cdot 2 \cdot 14 : 43 i

x_{1, 2} = \frac{- 8 \pm 4 3 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4 3 i}{2 \cdot 2}, x_{2} = \frac{- 8 - 4 3 i}{2 \cdot 2}

x = \frac{- 8 + 4 3 i}{2 \cdot 2} : - 2 + 3 i

x = \frac{- 8 - 4 3 i}{2 \cdot 2} : - 2 - 3 i

The solutions to the quadratic equation are:

x = - 2 + 3 i, x = - 2 - 3 i

10 x = x^{2}

\frac{7 ^{8}}{7 ^{6}}

2 + x \geq 3 (x - 1)

2 x^{2} + 17 x + 26 = 0

(2 f g^{4})^{4} (f g)^{6}

What are the solutions to the equation 2x^2+8x+14=0 ?
The solutions to the equation 2x^2+8x+14=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i
Find the zeros of 2x^2+8x+14=0
The zeros of 2x^2+8x+14=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i