What is x^2-6x+6<= 0 ?

The solution to x^2-6x+6<= 0 is -sqrt(3)+3<= x<= sqrt(3)+3

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x^2-6x+6<= 0

x^{2} - 6 x + 6 \leq 0

- 3 + 3 \leq x \leq 3 + 3

Interval Notation

[- 3 + 3, 3 + 3]

Decimal Notation

1.26794 \dots \leq x \leq 4.73205 \dots

Solution steps

x^{2} - 6 x + 6 \leq 0

Complete the square

x^{2} - 6 x + 6 : (x - 3)^{2} - 3

(x - 3)^{2} - 3 \leq 0

Move

3

to the right side

(x - 3)^{2} \leq 3

For

u^{n} \leq a

, if

n

is even then

- 3 \leq x - 3 \leq 3

a \leq u \leq b

then

a \leq u and u \leq b

- 3 \leq x - 3 and x - 3 \leq 3

- 3 \leq x - 3 : x \geq - 3 + 3

x - 3 \leq 3 : x \leq 3 + 3

Combine the intervals

x \geq - 3 + 3 and x \leq 3 + 3

Merge Overlapping Intervals

- 3 + 3 \leq x \leq 3 + 3

x = 1 - x^{2}

2 w^{3} - 8 w^{2} - 90 w

- 6 r + 3 = - 39

(\frac{m ^{- 1} m ^{5}}{m ^{- 2}})^{- 3}

x^{2} + (\frac{1}{6})^{2} = 1^{2}

What is x^2-6x+6<= 0 ?
The solution to x^2-6x+6<= 0 is -sqrt(3)+3<= x<= sqrt(3)+3