What is factor 4x^3+35x^2+88x+48 ?

The solution to factor 4x^3+35x^2+88x+48 is (4x+3)(x+4)^2

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factor 4x^3+35x^2+88x+48

factor

4 x^{3} + 35 x^{2} + 88 x + 48

(4 x + 3) (x + 4)^{2}

Solution steps

4 x^{3} + 35 x^{2} + 88 x + 48

Use the rational root theorem

= (4 x + 3) \frac{4 x ^{3} + 35 x ^{2} + 88 x + 48}{4 x + 3}

\frac{4 x ^{3} + 35 x ^{2} + 88 x + 48}{4 x + 3} = x^{2} + 8 x + 16

= (4 x + 3) (x^{2} + 8 x + 16)

Factor

x^{2} + 8 x + 16 : (x + 4) (x + 4)

= (4 x + 3) (x + 4) (x + 4)

Apply exponent rule:

aa = a^{2}

(x + 4) (x + 4) = (x + 4)^{2}

= (4 x + 3) (x + 4)^{2}

4 (x - 3) - 7 < 2 (x - 3)

(64)^{\frac{5}{6}}

12 x^{2} - 13 x - 4

\frac{2}{2 + 1}

q^{2} - q - 56

What is factor 4x^3+35x^2+88x+48 ?
The solution to factor 4x^3+35x^2+88x+48 is (4x+3)(x+4)^2