What are the solutions to the equation x^2-10x+26=8 ?

The solutions to the equation x^2-10x+26=8 are x=5+sqrt(7),x=5-sqrt(7)

Find the zeros of x^2-10x+26=8

The zeros of x^2-10x+26=8 are x=5+sqrt(7),x=5-sqrt(7)

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x^{2} - 10 x + 26 = 8

x = 5 + 7, x = 5 - 7

Decimal Notation

x = 7.64575 \dots, x = 2.35424 \dots

Solution steps

x^{2} - 10 x + 26 = 8

Move

8

to the left side

x^{2} - 10 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 18 = 27

x_{1, 2} = \frac{- ( - 10 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 7}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 7}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 7}{2 \cdot 1} : 5 + 7

x = \frac{- ( - 10 ) - 2 7}{2 \cdot 1} : 5 - 7

The solutions to the quadratic equation are:

x = 5 + 7, x = 5 - 7

4 x^{4} - 25 y^{2}

3 \times 9 + 10 \times \frac{36}{6}

\frac{2 x + 4}{3} \geq \frac{x}{6} - 3

21 x^{2} \geq - 11 x + 2

e^{- l n (x^{2})}

What are the solutions to the equation x^2-10x+26=8 ?
The solutions to the equation x^2-10x+26=8 are x=5+sqrt(7),x=5-sqrt(7)
Find the zeros of x^2-10x+26=8
The zeros of x^2-10x+26=8 are x=5+sqrt(7),x=5-sqrt(7)