What are the solutions to the equation b^2= 16/121 ?

The solutions to the equation b^2= 16/121 are b= 4/11 ,b=-4/11

Find the zeros of b^2= 16/121

The zeros of b^2= 16/121 are b= 4/11 ,b=-4/11

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b^{2} = \frac{16}{121}

b = \frac{4}{11}, b = - \frac{4}{11}

Solution steps

b^{2} = \frac{16}{121}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{16}{121}, b = - \frac{16}{121}

\frac{16}{121} = \frac{4}{11}

- \frac{16}{121} = - \frac{4}{11}

b = \frac{4}{11}, b = - \frac{4}{11}

2 - 8 y^{2} + 4 y - 6

- 4 < k - 3

10 x^{3} - 15 x

11 = 3 - 2 x

\frac{x ^{5}}{x ^{5}}

What are the solutions to the equation b^2= 16/121 ?
The solutions to the equation b^2= 16/121 are b= 4/11 ,b=-4/11
Find the zeros of b^2= 16/121
The zeros of b^2= 16/121 are b= 4/11 ,b=-4/11