What are the solutions to the equation 0=4x^2+3x+8 ?

The solutions to the equation 0=4x^2+3x+8 are x=-3/8+i(sqrt(119))/8 ,x=-3/8-i(sqrt(119))/8

Find the zeros of 0=4x^2+3x+8

The zeros of 0=4x^2+3x+8 are x=-3/8+i(sqrt(119))/8 ,x=-3/8-i(sqrt(119))/8

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0 = 4 x^{2} + 3 x + 8

x = - \frac{3}{8} + i \frac{119}{8}, x = - \frac{3}{8} - i \frac{119}{8}

Solution steps

0 = 4 x^{2} + 3 x + 8

Switch sides

4 x^{2} + 3 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 \cdot 8}{2 \cdot 4}

Simplify

3^{2} - 4 \cdot 4 \cdot 8 : 119 i

x_{1, 2} = \frac{- 3 \pm 119 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 119 i}{2 \cdot 4}, x_{2} = \frac{- 3 - 119 i}{2 \cdot 4}

x = \frac{- 3 + 119 i}{2 \cdot 4} : - \frac{3}{8} + i \frac{119}{8}

x = \frac{- 3 - 119 i}{2 \cdot 4} : - \frac{3}{8} - i \frac{119}{8}

The solutions to the quadratic equation are:

x = - \frac{3}{8} + i \frac{119}{8}, x = - \frac{3}{8} - i \frac{119}{8}

- 2 x > - 3

62 5^{\frac{1}{2}}

\frac{1}{\frac{1}{10}}

15 w^{2} + 28 w + 3 = - 2

\frac{x + y}{x - y}

What are the solutions to the equation 0=4x^2+3x+8 ?
The solutions to the equation 0=4x^2+3x+8 are x=-3/8+i(sqrt(119))/8 ,x=-3/8-i(sqrt(119))/8
Find the zeros of 0=4x^2+3x+8
The zeros of 0=4x^2+3x+8 are x=-3/8+i(sqrt(119))/8 ,x=-3/8-i(sqrt(119))/8