What are the solutions to the equation 4.4=-0.5x^2+1.15x+4.3 ?

The solutions to the equation 4.4=-0.5x^2+1.15x+4.3 are x=(23-sqrt(449))/(20),x=(23+sqrt(449))/(20)

Find the zeros of 4.4=-0.5x^2+1.15x+4.3

The zeros of 4.4=-0.5x^2+1.15x+4.3 are x=(23-sqrt(449))/(20),x=(23+sqrt(449))/(20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4.4 = - 0.5 x^{2} + 1.15 x + 4.3

x = \frac{23 - 449}{20}, x = \frac{23 + 449}{20}

Decimal Notation

x = 0.09051 \dots, x = 2.20948 \dots

Solution steps

4.4 = - 0.5 x^{2} + 1.15 x + 4.3

Multiply both sides by

100

440 = - 50 x^{2} + 115 x + 430

Switch sides

- 50 x^{2} + 115 x + 430 = 440

Move

440

to the left side

- 50 x^{2} + 115 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 115 \pm 11 5 ^{2} - 4 ( - 50 ) ( - 10 )}{2 ( - 50 )}

11 5^{2} - 4 (- 50) (- 10) = 5449

x_{1, 2} = \frac{- 115 \pm 5 449}{2 ( - 50 )}

Separate the solutions

x_{1} = \frac{- 115 + 5 449}{2 ( - 50 )}, x_{2} = \frac{- 115 - 5 449}{2 ( - 50 )}

x = \frac{- 115 + 5 449}{2 ( - 50 )} : \frac{23 - 449}{20}

x = \frac{- 115 - 5 449}{2 ( - 50 )} : \frac{23 + 449}{20}

The solutions to the quadratic equation are:

x = \frac{23 - 449}{20}, x = \frac{23 + 449}{20}

\frac{3 x ^{2} - 9 x + 12}{x ^{2} - 10 x + 25}

4 x^{2} + 11 x + 6

6 x^{3} - 16 x^{2} + 21 x - 56

12 x y + 20 x a - 84 a y - 140 a^{2}

3 (x - 3) = 3

What are the solutions to the equation 4.4=-0.5x^2+1.15x+4.3 ?
The solutions to the equation 4.4=-0.5x^2+1.15x+4.3 are x=(23-sqrt(449))/(20),x=(23+sqrt(449))/(20)
Find the zeros of 4.4=-0.5x^2+1.15x+4.3
The zeros of 4.4=-0.5x^2+1.15x+4.3 are x=(23-sqrt(449))/(20),x=(23+sqrt(449))/(20)