What are the solutions to the equation u^2-3u=(-5)/4 ?

The solutions to the equation u^2-3u=(-5)/4 are u= 5/2 ,u= 1/2

Find the zeros of u^2-3u=(-5)/4

The zeros of u^2-3u=(-5)/4 are u= 5/2 ,u= 1/2

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u^{2} - 3 u = \frac{- 5}{4}

u = \frac{5}{2}, u = \frac{1}{2}

Decimal Notation

u = 2.5, u = 0.5

Solution steps

u^{2} - 3 u = \frac{- 5}{4}

Multiply both sides by

4

4 u^{2} - 12 u = - 5

Move

5

to the left side

4 u^{2} - 12 u + 5 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 5 = 8

u_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 4}

Separate the solutions

u_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 4}, u_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 4}

u = \frac{- ( - 12 ) + 8}{2 \cdot 4} : \frac{5}{2}

u = \frac{- ( - 12 ) - 8}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

u = \frac{5}{2}, u = \frac{1}{2}

30 = - b + 23

- x^{2} + 81 x - 81 > 0

(2 - 2 i)^{2}

\frac{15 a ^{3}}{3 a}

x + 6 = 7

What are the solutions to the equation u^2-3u=(-5)/4 ?
The solutions to the equation u^2-3u=(-5)/4 are u= 5/2 ,u= 1/2
Find the zeros of u^2-3u=(-5)/4
The zeros of u^2-3u=(-5)/4 are u= 5/2 ,u= 1/2