What are the solutions to the equation a^2-2a=0 ?

The solutions to the equation a^2-2a=0 are a=2,a=0

Find the zeros of a^2-2a=0

The zeros of a^2-2a=0 are a=2,a=0

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a^{2} - 2 a = 0

a = 2, a = 0

Solution steps

a^{2} - 2 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

a_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, a_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

a = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

a = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

a = 2, a = 0

2 p x - 3 y + p y - 6 x

2 d^{2} + 15 d + 23 = 3

3 n^{3} - 3 n

n^{\frac{1}{2 ^{l o g_{2} (l o g_{2} (n))}}}

20 (\frac{π}{4})

What are the solutions to the equation a^2-2a=0 ?
The solutions to the equation a^2-2a=0 are a=2,a=0
Find the zeros of a^2-2a=0
The zeros of a^2-2a=0 are a=2,a=0