What are the solutions to the equation (7x-1)^2+1=0 ?

The solutions to the equation (7x-1)^2+1=0 are x= 1/7+i 1/7 ,x= 1/7-i 1/7

Find the zeros of (7x-1)^2+1=0

The zeros of (7x-1)^2+1=0 are x= 1/7+i 1/7 ,x= 1/7-i 1/7

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(7 x - 1)^{2} + 1 = 0

x = \frac{1}{7} + i \frac{1}{7}, x = \frac{1}{7} - i \frac{1}{7}

Solution steps

(7 x - 1)^{2} + 1 = 0

Move

1

to the right side

(7 x - 1)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 x - 1 = - 1 : x = \frac{1}{7} + i \frac{1}{7}

Solve

7 x - 1 = - - 1 : x = \frac{1}{7} - i \frac{1}{7}

The solutions to the quadratic equation are:

x = \frac{1}{7} + i \frac{1}{7}, x = \frac{1}{7} - i \frac{1}{7}

2 (2 x - 4) = 3 (2 x - 4)

∣ 5 x - 1 ∣ > 14

3 x^{2} - 16 x + 21

- 4 x^{6} y^{7}

6 a^{2} + 9 a - 27

What are the solutions to the equation (7x-1)^2+1=0 ?
The solutions to the equation (7x-1)^2+1=0 are x= 1/7+i 1/7 ,x= 1/7-i 1/7
Find the zeros of (7x-1)^2+1=0
The zeros of (7x-1)^2+1=0 are x= 1/7+i 1/7 ,x= 1/7-i 1/7