What are the solutions to the equation -x^2+4x+5=0 ?

The solutions to the equation -x^2+4x+5=0 are x=-1,x=5

Find the zeros of -x^2+4x+5=0

The zeros of -x^2+4x+5=0 are x=-1,x=5

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- x^{2} + 4 x + 5 = 0

x = - 1, x = 5

Solution steps

- x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 5 = 6

x_{1, 2} = \frac{- 4 \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 6}{2 ( - 1 )}, x_{2} = \frac{- 4 - 6}{2 ( - 1 )}

x = \frac{- 4 + 6}{2 ( - 1 )} : - 1

x = \frac{- 4 - 6}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = - 1, x = 5

∣ 4 - 3 z ∣ + 12 < 6

\frac{1}{4} + \frac{1}{5} + \frac{1}{6}

7 x^{2} - 0.12 x - 0.0036 = 0

9 m + 10 - 14 m = - 5

3 ∣ x + 1 ∣ - 5 = - 11

What are the solutions to the equation -x^2+4x+5=0 ?
The solutions to the equation -x^2+4x+5=0 are x=-1,x=5
Find the zeros of -x^2+4x+5=0
The zeros of -x^2+4x+5=0 are x=-1,x=5