What are the solutions to the equation 5x^2+9x-72=0 ?

The solutions to the equation 5x^2+9x-72=0 are x=3,x=-24/5

Find the zeros of 5x^2+9x-72=0

The zeros of 5x^2+9x-72=0 are x=3,x=-24/5

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5 x^{2} + 9 x - 72 = 0

x = 3, x = - \frac{24}{5}

Decimal Notation

x = 3, x = - 4.8

Solution steps

5 x^{2} + 9 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 72 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 72) = 39

x_{1, 2} = \frac{- 9 \pm 39}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 39}{2 \cdot 5}, x_{2} = \frac{- 9 - 39}{2 \cdot 5}

x = \frac{- 9 + 39}{2 \cdot 5} : 3

x = \frac{- 9 - 39}{2 \cdot 5} : - \frac{24}{5}

The solutions to the quadratic equation are:

x = 3, x = - \frac{24}{5}

- 4 ∣ c - 7 ∣ - 4 = - 8

2 \cdot (- 27)^{\frac{10}{3}}

\frac{s}{3} - 4 = 2

\frac{4 ^{5}}{4 ^{3}}

5 x^{3} - x^{2} + 15 x - 3

What are the solutions to the equation 5x^2+9x-72=0 ?
The solutions to the equation 5x^2+9x-72=0 are x=3,x=-24/5
Find the zeros of 5x^2+9x-72=0
The zeros of 5x^2+9x-72=0 are x=3,x=-24/5