What is ((-8y^{3/4})/(y^3z^6))^{-1/3} ?

The solution to ((-8y^{3/4})/(y^3z^6))^{-1/3} is -(z^2y^{3/4})/2

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simplify ((-8y^{3/4})/(y^3z^6))^{-1/3}

simplify

(\frac{- 8 y ^{\frac{3}{4}}}{y ^{3} z ^{6}})^{- \frac{1}{3}}

- \frac{z ^{2} y ^{\frac{3}{4}}}{2}

Solution steps

(\frac{- 8 y ^{\frac{3}{4}}}{y ^{3} z ^{6}})^{- \frac{1}{3}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{- 8 y ^{\frac{3}{4}}}{y ^{3} z ^{6}})^{- \frac{1}{3}} = \frac{1}{( \frac{- 8 y ^{\frac{3}{4}}}{y ^{3} z ^{6}} ) ^{\frac{1}{3}}}

= \frac{1}{( \frac{- 8 y ^{\frac{3}{4}}}{y ^{3} z ^{6}} ) ^{\frac{1}{3}}}

Simplify

(\frac{- 8 y ^{\frac{3}{4}}}{y ^{3} z ^{6}})^{\frac{1}{3}} : - \frac{2}{z ^{2} y ^{\frac{3}{4}}}

= \frac{1}{- \frac{2}{z ^{2} y ^{\frac{3}{4}}}}

Simplify

\frac{1}{- \frac{2}{z ^{2} y ^{\frac{3}{4}}}} : - \frac{z ^{2} y ^{\frac{3}{4}}}{2}

= - \frac{z ^{2} y ^{\frac{3}{4}}}{2}

(80 y)^{\frac{3}{4}}

8 (10 - k) = 2 k

10 m + 5 (4 m + 8) \geq 7 m - 6 - 2 m

- 2 x^{2} - 4 x + 70

\frac{2 + 3}{2} + \frac{1}{3}

What is ((-8y^{3/4})/(y^3z^6))^{-1/3} ?
The solution to ((-8y^{3/4})/(y^3z^6))^{-1/3} is -(z^2y^{3/4})/2