What is factor (a+b)^2-16 ?

The solution to factor (a+b)^2-16 is (a+b+4)(a+b-4)

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factor (a+b)^2-16

factor

(a + b)^{2} - 16

(a + b + 4) (a + b - 4)

Solution steps

(a + b)^{2} - 16

Factor the number:

16 = 4^{2}

= (a + b)^{2} - 4^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a + b)^{2} - 4^{2} = ((a + b) + 4) ((a + b) - 4)

= ((a + b) + 4) ((a + b) - 4)

Apply rule:

(a) = a

(a + b) = a + b

= (a + b + 4) (a + b - 4)

x^{5} - x^{4} - x^{3}

lo g_{64} (\frac{2}{4})

- \frac{12}{4}

4 x + 2 (x - 3) = 4 x + 2 x - 11

\frac{5 ^{- 2}}{5 ^{- 5}}