What are the solutions to the equation k^2-8k=0 ?

The solutions to the equation k^2-8k=0 are k=8,k=0

Find the zeros of k^2-8k=0

The zeros of k^2-8k=0 are k=8,k=0

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k^{2} - 8 k = 0

k = 8, k = 0

Solution steps

k^{2} - 8 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

k_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, k_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

k = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

k = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

k = 8, k = 0

18 x^{2} - 85 x + 18

(- 3 x^{2})^{2}

- 6 = 3 w^{2} - 11 w

9 + \frac{8 ^{3}}{2}

8 - 14

What are the solutions to the equation k^2-8k=0 ?
The solutions to the equation k^2-8k=0 are k=8,k=0
Find the zeros of k^2-8k=0
The zeros of k^2-8k=0 are k=8,k=0