What is ((2x+1)^2(2x-1)^3)/((x-1)^4)>0 ?

The solution to ((2x+1)^2(2x-1)^3)/((x-1)^4)>0 is 1/2 1

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((2x+1)^2(2x-1)^3)/((x-1)^4)>0

\frac{( 2 x + 1 ) ^{2} ( 2 x - 1 ) ^{3}}{( x - 1 ) ^{4}} > 0

\frac{1}{2} < x < 1 or x > 1

Interval Notation

(\frac{1}{2}, 1) \cup (1, \infty)

Decimal Notation

0.5 < x < 1 or x > 1

Solution steps

\frac{( 2 x + 1 ) ^{2} ( 2 x - 1 ) ^{3}}{( x - 1 ) ^{4}} > 0

Identify the intervals

\frac{1}{2} < x < 1 or x > 1

\frac{x ^{2}}{y ^{2}}

5 x^{2} - 7 x - 90 = 0

3 x^{2} - 25 x - 18

\frac{4}{11} n = \frac{16}{55}

2 x - 2 \geq - 12 and - 3 x > - 9

What is ((2x+1)^2(2x-1)^3)/((x-1)^4)>0 ?
The solution to ((2x+1)^2(2x-1)^3)/((x-1)^4)>0 is 1/2 <x<1\lor x>1