What are the solutions to the equation 10(x-7)^2=440 ?

The solutions to the equation 10(x-7)^2=440 are x=2sqrt(11)+7,x=-2sqrt(11)+7

Find the zeros of 10(x-7)^2=440

The zeros of 10(x-7)^2=440 are x=2sqrt(11)+7,x=-2sqrt(11)+7

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10 (x - 7)^{2} = 440

x = 211 + 7, x = - 211 + 7

Decimal Notation

x = 13.63324 \dots, x = 0.36675 \dots

Solution steps

10 (x - 7)^{2} = 440

Divide both sides by

10

(x - 7)^{2} = 44

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 44 : x = 211 + 7

Solve

x - 7 = - 44 : x = - 211 + 7

The solutions to the quadratic equation are:

x = 211 + 7, x = - 211 + 7

∣ x ∣ < 13

\frac{4}{( x ^{2} + 9 )} > 0

8 x - 12 = 15 x - 4 x

\frac{3 x + 14}{4} - 16 = - 15

∣ x - 9 ∣ = 2

What are the solutions to the equation 10(x-7)^2=440 ?
The solutions to the equation 10(x-7)^2=440 are x=2sqrt(11)+7,x=-2sqrt(11)+7
Find the zeros of 10(x-7)^2=440
The zeros of 10(x-7)^2=440 are x=2sqrt(11)+7,x=-2sqrt(11)+7