What are the solutions to the equation 6v^2-24v=0 ?

The solutions to the equation 6v^2-24v=0 are v=4,v=0

Find the zeros of 6v^2-24v=0

The zeros of 6v^2-24v=0 are v=4,v=0

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6 v^{2} - 24 v = 0

v = 4, v = 0

Solution steps

6 v^{2} - 24 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 24)^{2} - 4 \cdot 6 \cdot 0 = 24

v_{1, 2} = \frac{- ( - 24 ) \pm 24}{2 \cdot 6}

Separate the solutions

v_{1} = \frac{- ( - 24 ) + 24}{2 \cdot 6}, v_{2} = \frac{- ( - 24 ) - 24}{2 \cdot 6}

v = \frac{- ( - 24 ) + 24}{2 \cdot 6} : 4

v = \frac{- ( - 24 ) - 24}{2 \cdot 6} : 0

The solutions to the quadratic equation are:

v = 4, v = 0

12 = 4 x - 4

6 c^{2} + 7 c + 2

∣ 1 - 2 x ∣ \geq 3

4 (x - 9) + 52 = 2 (3 x + 17) + 2 x

8^{(\frac{1}{3})}

What are the solutions to the equation 6v^2-24v=0 ?
The solutions to the equation 6v^2-24v=0 are v=4,v=0
Find the zeros of 6v^2-24v=0
The zeros of 6v^2-24v=0 are v=4,v=0