What are the solutions to the equation 2x^2-0.45x-3=0 ?

The solutions to the equation 2x^2-0.45x-3=0 are x=(9+sqrt(9681))/(80),x=(9-sqrt(9681))/(80)

Find the zeros of 2x^2-0.45x-3=0

The zeros of 2x^2-0.45x-3=0 are x=(9+sqrt(9681))/(80),x=(9-sqrt(9681))/(80)

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2 x^{2} - 0.45 x - 3 = 0

x = \frac{9 + 9681}{80}, x = \frac{9 - 9681}{80}

Decimal Notation

x = 1.34240 \dots, x = - 1.11740 \dots

Solution steps

2 x^{2} - 0.45 x - 3 = 0

Multiply both sides by

100

200 x^{2} - 45 x - 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 45 ) \pm ( - 45 ) ^{2} - 4 \cdot 200 ( - 300 )}{2 \cdot 200}

(- 45)^{2} - 4 \cdot 200 (- 300) = 59681

x_{1, 2} = \frac{- ( - 45 ) \pm 5 9681}{2 \cdot 200}

Separate the solutions

x_{1} = \frac{- ( - 45 ) + 5 9681}{2 \cdot 200}, x_{2} = \frac{- ( - 45 ) - 5 9681}{2 \cdot 200}

x = \frac{- ( - 45 ) + 5 9681}{2 \cdot 200} : \frac{9 + 9681}{80}

x = \frac{- ( - 45 ) - 5 9681}{2 \cdot 200} : \frac{9 - 9681}{80}

The solutions to the quadratic equation are:

x = \frac{9 + 9681}{80}, x = \frac{9 - 9681}{80}

15 c \cdot (a + b) + 8 \cdot (b + a)

- 5 x^{3} + 6 x^{2} + 15 x - 18

x^{4} - x^{2} - 2 x - 1

∣ 6 - 3 x ∣ \leq 18

4 (9 - 3 x) + 9 (3 x + 2) = 144

What are the solutions to the equation 2x^2-0.45x-3=0 ?
The solutions to the equation 2x^2-0.45x-3=0 are x=(9+sqrt(9681))/(80),x=(9-sqrt(9681))/(80)
Find the zeros of 2x^2-0.45x-3=0
The zeros of 2x^2-0.45x-3=0 are x=(9+sqrt(9681))/(80),x=(9-sqrt(9681))/(80)