What are the solutions to the equation k^2-16k=17 ?

The solutions to the equation k^2-16k=17 are k=17,k=-1

Find the zeros of k^2-16k=17

The zeros of k^2-16k=17 are k=17,k=-1

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k^{2} - 16 k = 17

k = 17, k = - 1

Solution steps

k^{2} - 16 k = 17

Move

17

to the left side

k^{2} - 16 k - 17 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 17) = 18

k_{1, 2} = \frac{- ( - 16 ) \pm 18}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 16 ) + 18}{2 \cdot 1}, k_{2} = \frac{- ( - 16 ) - 18}{2 \cdot 1}

k = \frac{- ( - 16 ) + 18}{2 \cdot 1} : 17

k = \frac{- ( - 16 ) - 18}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

k = 17, k = - 1

x^{3} + x^{2} + 16 x + 16

x = 4!

m^{2} + 8 m

3 x - 5 = - 2 x^{2}

(x + 2) (x - 2) = 2 x - 1

What are the solutions to the equation k^2-16k=17 ?
The solutions to the equation k^2-16k=17 are k=17,k=-1
Find the zeros of k^2-16k=17
The zeros of k^2-16k=17 are k=17,k=-1