What are the solutions to the equation 8x^2+16x-36=10 ?

The solutions to the equation 8x^2+16x-36=10 are x=(-2+3sqrt(3))/2 ,x=-(2+3sqrt(3))/2

Find the zeros of 8x^2+16x-36=10

The zeros of 8x^2+16x-36=10 are x=(-2+3sqrt(3))/2 ,x=-(2+3sqrt(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} + 16 x - 36 = 10

x = \frac{- 2 + 3 3}{2}, x = - \frac{2 + 3 3}{2}

Decimal Notation

x = 1.59807 \dots, x = - 3.59807 \dots

Solution steps

8 x^{2} + 16 x - 36 = 10

Move

10

to the left side

8 x^{2} + 16 x - 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 8 ( - 46 )}{2 \cdot 8}

1 6^{2} - 4 \cdot 8 (- 46) = 243

x_{1, 2} = \frac{- 16 \pm 24 3}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 16 + 24 3}{2 \cdot 8}, x_{2} = \frac{- 16 - 24 3}{2 \cdot 8}

x = \frac{- 16 + 24 3}{2 \cdot 8} : \frac{- 2 + 3 3}{2}

x = \frac{- 16 - 24 3}{2 \cdot 8} : - \frac{2 + 3 3}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 3 3}{2}, x = - \frac{2 + 3 3}{2}

\frac{1}{3} + \frac{1}{4} + \frac{1}{6}

\frac{12 x ^{3}}{8 y}

2.6 + j = 7.1

s + 1 \geq - 5

3 (x - 2) - 4 x = 2 (x - 9)

What are the solutions to the equation 8x^2+16x-36=10 ?
The solutions to the equation 8x^2+16x-36=10 are x=(-2+3sqrt(3))/2 ,x=-(2+3sqrt(3))/2
Find the zeros of 8x^2+16x-36=10
The zeros of 8x^2+16x-36=10 are x=(-2+3sqrt(3))/2 ,x=-(2+3sqrt(3))/2