What are the solutions to the equation -2/3 x^2-x+2=0 ?

The solutions to the equation -2/3 x^2-x+2=0 are x=-(3+sqrt(57))/4 ,x=(sqrt(57)-3)/4

Find the zeros of -2/3 x^2-x+2=0

The zeros of -2/3 x^2-x+2=0 are x=-(3+sqrt(57))/4 ,x=(sqrt(57)-3)/4

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- \frac{2}{3} x^{2} - x + 2 = 0

x = - \frac{3 + 57}{4}, x = \frac{57 - 3}{4}

Decimal Notation

x = - 2.63745 \dots, x = 1.13745 \dots

Solution steps

- \frac{2}{3} x^{2} - x + 2 = 0

Multiply both sides by

3

- 2 x^{2} - 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

(- 3)^{2} - 4 (- 2) \cdot 6 = 57

x_{1, 2} = \frac{- ( - 3 ) \pm 57}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 57}{2 ( - 2 )}, x_{2} = \frac{- ( - 3 ) - 57}{2 ( - 2 )}

x = \frac{- ( - 3 ) + 57}{2 ( - 2 )} : - \frac{3 + 57}{4}

x = \frac{- ( - 3 ) - 57}{2 ( - 2 )} : \frac{57 - 3}{4}

The solutions to the quadratic equation are:

x = - \frac{3 + 57}{4}, x = \frac{57 - 3}{4}

2 - \frac{7}{3}

12 5^{\frac{1}{3}}

37 x + \frac{1}{2} - (x + \frac{1}{4}) = 9 (4 x - 7) + 5

(a + 1)^{2} - 4 (a + 1)

2 x^{2} = 6 x - 5

What are the solutions to the equation -2/3 x^2-x+2=0 ?
The solutions to the equation -2/3 x^2-x+2=0 are x=-(3+sqrt(57))/4 ,x=(sqrt(57)-3)/4
Find the zeros of -2/3 x^2-x+2=0
The zeros of -2/3 x^2-x+2=0 are x=-(3+sqrt(57))/4 ,x=(sqrt(57)-3)/4