What are the solutions to the equation a^2+7a+6=a+1 ?

The solutions to the equation a^2+7a+6=a+1 are a=-1,a=-5

Find the zeros of a^2+7a+6=a+1

The zeros of a^2+7a+6=a+1 are a=-1,a=-5

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a^{2} + 7 a + 6 = a + 1

a = - 1, a = - 5

Solution steps

a^{2} + 7 a + 6 = a + 1

Move

1

to the left side

a^{2} + 7 a + 5 = a

Move

a

to the left side

a^{2} + 6 a + 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 5 = 4

a_{1, 2} = \frac{- 6 \pm 4}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 6 + 4}{2 \cdot 1}, a_{2} = \frac{- 6 - 4}{2 \cdot 1}

a = \frac{- 6 + 4}{2 \cdot 1} : - 1

a = \frac{- 6 - 4}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

a = - 1, a = - 5

∣ x - 15 ∣ = 30

f = 0^{2} - 3

4^{2} + 2^{2}

x^{2} = 4 x + 60

x + 4 = x^{2} - 2

What are the solutions to the equation a^2+7a+6=a+1 ?
The solutions to the equation a^2+7a+6=a+1 are a=-1,a=-5
Find the zeros of a^2+7a+6=a+1
The zeros of a^2+7a+6=a+1 are a=-1,a=-5