What are the solutions to the equation 3^2+7^2=c^2 ?

The solutions to the equation 3^2+7^2=c^2 are c=sqrt(58),c=-sqrt(58)

Find the zeros of 3^2+7^2=c^2

The zeros of 3^2+7^2=c^2 are c=sqrt(58),c=-sqrt(58)

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3^{2} + 7^{2} = c^{2}

c = 58, c = - 58

Decimal Notation

c = 7.61577 \dots, c = - 7.61577 \dots

Solution steps

3^{2} + 7^{2} = c^{2}

Switch sides

c^{2} = 3^{2} + 7^{2}

Simplify

3^{2} + 7^{2} : 58

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 58, c = - 58

1 - \frac{4}{5}

4 x^{3} - x^{2} - 4 x + 1

x + 2 = - 2

0. 2^{2}

4 x - 11 = - 2 x + 1

What are the solutions to the equation 3^2+7^2=c^2 ?
The solutions to the equation 3^2+7^2=c^2 are c=sqrt(58),c=-sqrt(58)
Find the zeros of 3^2+7^2=c^2
The zeros of 3^2+7^2=c^2 are c=sqrt(58),c=-sqrt(58)