What are the solutions to the equation -8x+3x^2=-18 ?

The solutions to the equation -8x+3x^2=-18 are x= 4/3+i(sqrt(38))/3 ,x= 4/3-i(sqrt(38))/3

Find the zeros of -8x+3x^2=-18

The zeros of -8x+3x^2=-18 are x= 4/3+i(sqrt(38))/3 ,x= 4/3-i(sqrt(38))/3

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- 8 x + 3 x^{2} = - 18

x = \frac{4}{3} + i \frac{38}{3}, x = \frac{4}{3} - i \frac{38}{3}

Solution steps

- 8 x + 3 x^{2} = - 18

Move

18

to the left side

- 8 x + 3 x^{2} + 18 = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 8 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 18}{2 \cdot 3}

Simplify

(- 8)^{2} - 4 \cdot 3 \cdot 18 : 238 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 38 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 38 i}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 2 38 i}{2 \cdot 3}

x = \frac{- ( - 8 ) + 2 38 i}{2 \cdot 3} : \frac{4}{3} + i \frac{38}{3}

x = \frac{- ( - 8 ) - 2 38 i}{2 \cdot 3} : \frac{4}{3} - i \frac{38}{3}

The solutions to the quadratic equation are:

x = \frac{4}{3} + i \frac{38}{3}, x = \frac{4}{3} - i \frac{38}{3}

2 - \frac{9}{5}

2 - 4

24 ab c - 10 a c

6 x^{2} + 31 x + 18

7 x - 1 = 4 x + 5

What are the solutions to the equation -8x+3x^2=-18 ?
The solutions to the equation -8x+3x^2=-18 are x= 4/3+i(sqrt(38))/3 ,x= 4/3-i(sqrt(38))/3
Find the zeros of -8x+3x^2=-18
The zeros of -8x+3x^2=-18 are x= 4/3+i(sqrt(38))/3 ,x= 4/3-i(sqrt(38))/3