What are the solutions to the equation -2x^2+8x-9=0 ?

The solutions to the equation -2x^2+8x-9=0 are x=2-i(sqrt(2))/2 ,x=2+i(sqrt(2))/2

Find the zeros of -2x^2+8x-9=0

The zeros of -2x^2+8x-9=0 are x=2-i(sqrt(2))/2 ,x=2+i(sqrt(2))/2

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- 2 x^{2} + 8 x - 9 = 0

x = 2 - i \frac{2}{2}, x = 2 + i \frac{2}{2}

Solution steps

- 2 x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 9 )}{2 ( - 2 )}

Simplify

8^{2} - 4 (- 2) (- 9) : 22 i

x_{1, 2} = \frac{- 8 \pm 2 2 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 2 i}{2 ( - 2 )}, x_{2} = \frac{- 8 - 2 2 i}{2 ( - 2 )}

x = \frac{- 8 + 2 2 i}{2 ( - 2 )} : 2 - i \frac{2}{2}

x = \frac{- 8 - 2 2 i}{2 ( - 2 )} : 2 + i \frac{2}{2}

The solutions to the quadratic equation are:

x = 2 - i \frac{2}{2}, x = 2 + i \frac{2}{2}

\frac{( - 2 m n ^{2} ) ^{- 3}}{4 m ^{- 6} n ^{4}}

2 < 1 - 4 x \leq 8

\frac{4}{5} + 3

3 x + 2 = 32

8 x^{2} + 3 = 10 x

What are the solutions to the equation -2x^2+8x-9=0 ?
The solutions to the equation -2x^2+8x-9=0 are x=2-i(sqrt(2))/2 ,x=2+i(sqrt(2))/2
Find the zeros of -2x^2+8x-9=0
The zeros of -2x^2+8x-9=0 are x=2-i(sqrt(2))/2 ,x=2+i(sqrt(2))/2