What are the solutions to the equation y^2-y-72=0 ?

The solutions to the equation y^2-y-72=0 are y=9,y=-8

Find the zeros of y^2-y-72=0

The zeros of y^2-y-72=0 are y=9,y=-8

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y^{2} - y - 72 = 0

y = 9, y = - 8

Solution steps

y^{2} - y - 72 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 72) = 17

y_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 1}, y_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 1}

y = \frac{- ( - 1 ) + 17}{2 \cdot 1} : 9

y = \frac{- ( - 1 ) - 17}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

y = 9, y = - 8

\frac{- \frac{1}{2}}{\frac{3}{2}}

\frac{7}{2} - \frac{7}{6}

\frac{3 n ^{4}}{3 n ^{3}}

∣ 4 - 3 x ∣ > 7

- 15 - x^{2} < 8 x

What are the solutions to the equation y^2-y-72=0 ?
The solutions to the equation y^2-y-72=0 are y=9,y=-8
Find the zeros of y^2-y-72=0
The zeros of y^2-y-72=0 are y=9,y=-8