What are the solutions to the equation -4(x+2)^2=-20 ?

The solutions to the equation -4(x+2)^2=-20 are x=sqrt(5)-2,x=-sqrt(5)-2

Find the zeros of -4(x+2)^2=-20

The zeros of -4(x+2)^2=-20 are x=sqrt(5)-2,x=-sqrt(5)-2

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- 4 (x + 2)^{2} = - 20

x = 5 - 2, x = - 5 - 2

Decimal Notation

x = 0.23606 \dots, x = - 4.23606 \dots

Solution steps

- 4 (x + 2)^{2} = - 20

Divide both sides by

- 4

(x + 2)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 5 : x = 5 - 2

Solve

x + 2 = - 5 : x = - 5 - 2

The solutions to the quadratic equation are:

x = 5 - 2, x = - 5 - 2

z = \frac{1}{( 1 + i ) ( 1 - 2 i ) ( 1 + 3 i )}

3 x^{2} + 4 x y - 4 y^{2}

\frac{1}{4} < \frac{x}{5} < \frac{2}{3}

6 a + 3 = 45

\frac{2 ^{n + 1}}{2 ^{n}}

What are the solutions to the equation -4(x+2)^2=-20 ?
The solutions to the equation -4(x+2)^2=-20 are x=sqrt(5)-2,x=-sqrt(5)-2
Find the zeros of -4(x+2)^2=-20
The zeros of -4(x+2)^2=-20 are x=sqrt(5)-2,x=-sqrt(5)-2