What are the solutions to the equation 16(9-3x)^2+13=49 ?

The solutions to the equation 16(9-3x)^2+13=49 are x= 5/2 ,x= 7/2

Find the zeros of 16(9-3x)^2+13=49

The zeros of 16(9-3x)^2+13=49 are x= 5/2 ,x= 7/2

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16 (9 - 3 x)^{2} + 13 = 49

x = \frac{5}{2}, x = \frac{7}{2}

Decimal Notation

x = 2.5, x = 3.5

Solution steps

16 (9 - 3 x)^{2} + 13 = 49

Move

13

to the right side

16 (9 - 3 x)^{2} = 36

Divide both sides by

16

(9 - 3 x)^{2} = \frac{9}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

9 - 3 x = \frac{9}{4} : x = \frac{5}{2}

Solve

9 - 3 x = - \frac{9}{4} : x = \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{7}{2}

x^{2} + 5 = 3 x + 5

25 r^{2} + 20 r + 4

\frac{x ^{\frac{1}{2}}}{x ^{2}}

x^{2} - x - 0.25 = 0

What are the solutions to the equation 16(9-3x)^2+13=49 ?
The solutions to the equation 16(9-3x)^2+13=49 are x= 5/2 ,x= 7/2
Find the zeros of 16(9-3x)^2+13=49
The zeros of 16(9-3x)^2+13=49 are x= 5/2 ,x= 7/2