What are the solutions to the equation 2=c^2+c ?

The solutions to the equation 2=c^2+c are c=1,c=-2

Find the zeros of 2=c^2+c

The zeros of 2=c^2+c are c=1,c=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 = c^{2} + c

c = 1, c = - 2

Solution steps

2 = c^{2} + c

Switch sides

c^{2} + c = 2

Move

2

to the left side

c^{2} + c - 2 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

c_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 1 + 3}{2 \cdot 1}, c_{2} = \frac{- 1 - 3}{2 \cdot 1}

c = \frac{- 1 + 3}{2 \cdot 1} : 1

c = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

c = 1, c = - 2

\frac{n}{12} = - 5 - 11

\frac{m + 4}{3} > 3

144 x^{3} y^{4} z^{5}

4 r^{3} - 3 r^{2} - 4 r + 3

2 x^{2} + 7 x + 3

What are the solutions to the equation 2=c^2+c ?
The solutions to the equation 2=c^2+c are c=1,c=-2
Find the zeros of 2=c^2+c
The zeros of 2=c^2+c are c=1,c=-2