What is 1/(-1+y)(-x+(x^2)/2) ?

The solution to 1/(-1+y)(-x+(x^2)/2) is (-2x+x^2)/(2(-1+y))

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simplify 1/(-1+y)(-x+(x^2)/2)

simplify

\frac{1}{- 1 + y} (- x + \frac{x ^{2}}{2})

\frac{- 2 x + x ^{2}}{2 ( - 1 + y )}

Solution steps

\frac{1}{- 1 + y} (- x + \frac{x ^{2}}{2})

Simplify

- x + \frac{x ^{2}}{2} : \frac{- 2 x + x ^{2}}{2}

= \frac{1}{- 1 + y} \cdot \frac{- 2 x + x ^{2}}{2}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot ( - 2 x + x ^{2} )}{( - 1 + y ) \cdot 2}

Apply rule:

1 \cdot a = a

1 \cdot (- 2 x + x^{2}) = (- 2 x + x^{2})

= \frac{- 2 x + x ^{2}}{( - 1 + y ) \cdot 2}

= \frac{- 2 x + x ^{2}}{2 ( - 1 + y )}

\frac{( 3 - 5 i )}{( 2 - 5 i )}

\frac{1}{3} (6 + x) - 5 = 12

4 (x + h)^{2} - 2 (x + h) - (4 x^{2} - 2 x)

- x^{2} - 8 x - 12

(- \frac{1}{5})^{2}

What is 1/(-1+y)(-x+(x^2)/2) ?
The solution to 1/(-1+y)(-x+(x^2)/2) is (-2x+x^2)/(2(-1+y))