What are the solutions to the equation r^2-8r-9=0 ?

The solutions to the equation r^2-8r-9=0 are r=9,r=-1

Find the zeros of r^2-8r-9=0

The zeros of r^2-8r-9=0 are r=9,r=-1

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r^{2} - 8 r - 9 = 0

r = 9, r = - 1

Solution steps

r^{2} - 8 r - 9 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 9) = 10

r_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 10}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 10}{2 \cdot 1}

r = \frac{- ( - 8 ) + 10}{2 \cdot 1} : 9

r = \frac{- ( - 8 ) - 10}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

r = 9, r = - 1

\frac{5}{6} = \frac{x}{16}

3 \leq x \leq 7

40 + 810 + 90

4 - 2

\frac{x}{e ^{x}} \geq - 0.2679

What are the solutions to the equation r^2-8r-9=0 ?
The solutions to the equation r^2-8r-9=0 are r=9,r=-1
Find the zeros of r^2-8r-9=0
The zeros of r^2-8r-9=0 are r=9,r=-1