What are the solutions to the equation x(x-13)+40=0 ?

The solutions to the equation x(x-13)+40=0 are x=8,x=5

Find the zeros of x(x-13)+40=0

The zeros of x(x-13)+40=0 are x=8,x=5

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x (x - 13) + 40 = 0

x = 8, x = 5

Solution steps

x (x - 13) + 40 = 0

Expand

x (x - 13) + 40 : x^{2} - 13 x + 40

x^{2} - 13 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 40 = 3

x_{1, 2} = \frac{- ( - 13 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 3}{2 \cdot 1}

x = \frac{- ( - 13 ) + 3}{2 \cdot 1} : 8

x = \frac{- ( - 13 ) - 3}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 8, x = 5

3 x^{3} + 21 x^{2} - 54 x

y^{2} + y + 6 = 0

∣ x - 2 ∣ + ∣ x + 1 ∣ = - 1

\frac{u}{- 6} = 6

\frac{1}{2} x + 5 = \frac{1}{6} x + 6

What are the solutions to the equation x(x-13)+40=0 ?
The solutions to the equation x(x-13)+40=0 are x=8,x=5
Find the zeros of x(x-13)+40=0
The zeros of x(x-13)+40=0 are x=8,x=5