What is the answer to 5[3(x+2)+4]+2x=67 ?

The answer to 5[3(x+2)+4]+2x=67 is x=1

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5[3(x+2)+4]+2x=67

5 [3 (x + 2) + 4] + 2 x = 67

x = 1

Solution steps

5 [3 (x + 2) + 4] + 2 x = 67

Expand

5 (3 (x + 2) + 4) + 2 x : 17 x + 50

17 x + 50 = 67

Move

50

to the right side

17 x = 17

Divide both sides by

17

x = 1

4 (y + 3)^{2} = 0

(2 x - 1)^{2} = 26

8 (h - 1) = 6 h + 4 + 2 h

2 t + 1 + 2 t = 23 + 25 + 27 - t

9 x + 27 = 9 (x + 2) + 9

What is the answer to 5[3(x+2)+4]+2x=67 ?
The answer to 5[3(x+2)+4]+2x=67 is x=1
Solve for x: 5[3(x+2)+4]+2x=67
The solution is x=1