What are the solutions to the equation x^2+16x+17=0 ?

The solutions to the equation x^2+16x+17=0 are x=-8+sqrt(47),x=-8-sqrt(47)

Find the zeros of x^2+16x+17=0

The zeros of x^2+16x+17=0 are x=-8+sqrt(47),x=-8-sqrt(47)

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x^{2} + 16 x + 17 = 0

x = - 8 + 47, x = - 8 - 47

Decimal Notation

x = - 1.14434 \dots, x = - 14.85565 \dots

Solution steps

x^{2} + 16 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 17 = 247

x_{1, 2} = \frac{- 16 \pm 2 47}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 47}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 47}{2 \cdot 1}

x = \frac{- 16 + 2 47}{2 \cdot 1} : - 8 + 47

x = \frac{- 16 - 2 47}{2 \cdot 1} : - 8 - 47

The solutions to the quadratic equation are:

x = - 8 + 47, x = - 8 - 47

(- 5 x^{2} y^{3}) (3 x y^{- 2})

5 - c = - 15

- 2 (1) + 5

2 x + 3 > 5

(2 - 3)^{2}

What are the solutions to the equation x^2+16x+17=0 ?
The solutions to the equation x^2+16x+17=0 are x=-8+sqrt(47),x=-8-sqrt(47)
Find the zeros of x^2+16x+17=0
The zeros of x^2+16x+17=0 are x=-8+sqrt(47),x=-8-sqrt(47)