What are the solutions to the equation x^2-2x=0 ?

The solutions to the equation x^2-2x=0 are x=2,x=0

Find the zeros of x^2-2x=0

The zeros of x^2-2x=0 are x=2,x=0

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x^{2} - 2 x = 0

x = 2, x = 0

Solution steps

x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

x = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

\frac{b + 11}{3} = - 2

(5 - 3) (5 + 23)

x = \frac{- 6 - 6 ^{2} - 96}{2 \cdot 3}

\frac{8 ^{2}}{8 ^{- 4}}

- 9 \cdot \frac{1}{3}

What are the solutions to the equation x^2-2x=0 ?
The solutions to the equation x^2-2x=0 are x=2,x=0
Find the zeros of x^2-2x=0
The zeros of x^2-2x=0 are x=2,x=0