What are the solutions to the equation m^2+16m+40=0 ?

The solutions to the equation m^2+16m+40=0 are m=2(sqrt(6)-4),m=-2(4+sqrt(6))

Find the zeros of m^2+16m+40=0

The zeros of m^2+16m+40=0 are m=2(sqrt(6)-4),m=-2(4+sqrt(6))

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m^{2} + 16 m + 40 = 0

m = 2 (6 - 4), m = - 2 (4 + 6)

Decimal Notation

m = - 3.10102 \dots, m = - 12.89897 \dots

Solution steps

m^{2} + 16 m + 40 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 40 = 46

m_{1, 2} = \frac{- 16 \pm 4 6}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 16 + 4 6}{2 \cdot 1}, m_{2} = \frac{- 16 - 4 6}{2 \cdot 1}

m = \frac{- 16 + 4 6}{2 \cdot 1} : 2 (6 - 4)

m = \frac{- 16 - 4 6}{2 \cdot 1} : - 2 (4 + 6)

The solutions to the quadratic equation are:

m = 2 (6 - 4), m = - 2 (4 + 6)

y < 15 - 13

(27)^{\frac{1}{3}}

25 - 49 x^{2}

(y - 3)^{2} = 2 y - 10

a^{2} x^{2} - 3 b x^{2} + a^{2} y^{2} - 3 b y^{2}

What are the solutions to the equation m^2+16m+40=0 ?
The solutions to the equation m^2+16m+40=0 are m=2(sqrt(6)-4),m=-2(4+sqrt(6))
Find the zeros of m^2+16m+40=0
The zeros of m^2+16m+40=0 are m=2(sqrt(6)-4),m=-2(4+sqrt(6))