What is (x+2)/(|x|-4)<= 1 ?

The solution to (x+2)/(|x|-4)<= 1 is x<-4\lor-3<= x<4

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(x+2)/(|x|-4)<= 1

\frac{x + 2}{∣ x ∣ - 4} \leq 1

x < - 4 or - 3 \leq x < 4

Interval Notation

(- \infty, - 4) \cup [- 3, 4)

Solution steps

\frac{x + 2}{∣ x ∣ - 4} \leq 1

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

x < - 4 or - 3 \leq x < 0 or 0 \leq x < 4 or No Solution

Merge Overlapping Intervals

x < - 4 or - 3 \leq x < 4

25 + 6 x = 5 + x

4 \leq \frac{r}{14} + 10

2 x^{2} + 14 x - 16

35 \cdot 4

5 (- 4 + 5 a) < 31 + 8 a

What is (x+2)/(|x|-4)<= 1 ?
The solution to (x+2)/(|x|-4)<= 1 is x<-4\lor-3<= x<4