What are the solutions to the equation 3(z+12)^2-30=90 ?

The solutions to the equation 3(z+12)^2-30=90 are z=2sqrt(10)-12,z=-2sqrt(10)-12

Find the zeros of 3(z+12)^2-30=90

The zeros of 3(z+12)^2-30=90 are z=2sqrt(10)-12,z=-2sqrt(10)-12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (z + 12)^{2} - 30 = 90

z = 210 - 12, z = - 210 - 12

Decimal Notation

z = - 5.67544 \dots, z = - 18.32455 \dots

Solution steps

3 (z + 12)^{2} - 30 = 90

Move

30

to the right side

3 (z + 12)^{2} = 120

Divide both sides by

3

(z + 12)^{2} = 40

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 12 = 40 : z = 210 - 12

Solve

z + 12 = - 40 : z = - 210 - 12

The solutions to the quadratic equation are:

z = 210 - 12, z = - 210 - 12

x = - 120499.2233 + 62.7512 \cdot 1900

\frac{t}{6} \geq 16

4363

x^{2} - 3 > 0

\frac{2 2}{2}

What are the solutions to the equation 3(z+12)^2-30=90 ?
The solutions to the equation 3(z+12)^2-30=90 are z=2sqrt(10)-12,z=-2sqrt(10)-12
Find the zeros of 3(z+12)^2-30=90
The zeros of 3(z+12)^2-30=90 are z=2sqrt(10)-12,z=-2sqrt(10)-12