What are the solutions to the equation n^2+2n-24=0 ?

The solutions to the equation n^2+2n-24=0 are n=4,n=-6

Find the zeros of n^2+2n-24=0

The zeros of n^2+2n-24=0 are n=4,n=-6

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n^{2} + 2 n - 24 = 0

n = 4, n = - 6

Solution steps

n^{2} + 2 n - 24 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 24) = 10

n_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 2 + 10}{2 \cdot 1}, n_{2} = \frac{- 2 - 10}{2 \cdot 1}

n = \frac{- 2 + 10}{2 \cdot 1} : 4

n = \frac{- 2 - 10}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

n = 4, n = - 6

\frac{x}{x - 8} > 0

4 x (x + 1) - 7 (x + 1)^{2}

lo g_{3} (9)

2 x^{2} + 1 x - 15

- 3 x + 7 = - 2

What are the solutions to the equation n^2+2n-24=0 ?
The solutions to the equation n^2+2n-24=0 are n=4,n=-6
Find the zeros of n^2+2n-24=0
The zeros of n^2+2n-24=0 are n=4,n=-6